Question

How can we prove that BQ=CP from the give figure?

Answer 1

Given,

AB = AC

AP = AQ

Subtracting the LHS and RHS in the above equations,

AB - AP = AC - AQ

PB = QC

Considering triangles PBC and QCB,

PB = QC (just proven)

BC = BC (common base)

angle PBC = angle QCB (isosceles triangle property)

So, the two triangles are congruent with each other.

So, PC = QB. (Corresponding Pair of Congruent Triangles)

-WonderGirl

Answer 2

Hey

Uploading the shortest possible solution.. :)

Hope it helps ^_^