how can we say that the circumference of the bohr orbit of hydrogen is an integral multiple of de broglie wavelength??
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The angular momentum of an electron = mvr = nh/2π --------------1
Also according to de Broglie equation λ = h/mv
Or
mv = h/v -----------2
Putting 2 in 1
h/v =nh/2π or 2λr= nλ
Since ‘2πr’ represents the circumference of the Bohr orbit (r), it is proved by equation (3) that the circumference of the Bohr orbit of the hydrogen atom is an integral multiple of de Broglie’s wavelength associated with the electron revolving around the orbit.
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Also according to de Broglie equation λ = h/mv
Or
mv = h/v -----------2
Putting 2 in 1
h/v =nh/2π or 2λr= nλ
Since ‘2πr’ represents the circumference of the Bohr orbit (r), it is proved by equation (3) that the circumference of the Bohr orbit of the hydrogen atom is an integral multiple of de Broglie’s wavelength associated with the electron revolving around the orbit.
i think the answer will be helpful for u.
if doesn't help plz tell me
arushi112sharma:
thanks foe your help buddy ..
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