how can we solve 343acube-729bcube
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343a cube= (7a)^3
729b cube = (9b)^3
(7a)cube -(9b) cube =(7a - 9b)(7a square. +7a*9b+9b square
729b cube = (9b)^3
(7a)cube -(9b) cube =(7a - 9b)(7a square. +7a*9b+9b square
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Find the numbers whose cube is 343 and 729.
hence 7 is the cube root of 343 whereas 9 is the cube root of 729.
*(7a)3-(9b)3
Now
(7a-9b)cube=(7a)cube-3(7a square 9b)+3(7a 9b square)+9bcube
(the above equation is based on the (a-b)whole cube
hence 7 is the cube root of 343 whereas 9 is the cube root of 729.
*(7a)3-(9b)3
Now
(7a-9b)cube=(7a)cube-3(7a square 9b)+3(7a 9b square)+9bcube
(the above equation is based on the (a-b)whole cube
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