HOW CAN WE SOLVE A RIGHT ANGLE TRIANGLE HAVING AB=23 BC=25 AND FIND AC
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Answered by
3
√(23²+25²)=√1154=33.94~ 34
satyam8050:
Apply Pythagoras theorem
Answered by
2
we can solve it by Pythagoras theorem
AC^2=AB^2+BC^2
= 23^2+25^2
= 529+625
=1154
now take square root of 1154
AC^2=AB^2+BC^2
= 23^2+25^2
= 529+625
=1154
now take square root of 1154
but the answer is 3 root 6
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