Question

How can we solve these (in the below attachment) problems:

Answer 1

4 (II)184

In the first series,12-8=4 and 12+8=20

by multiplying them , we get 80 i.e. the result given

Similarly,25-21=4,25+21=46 and 4*46=184

So, 184 is the correct answer

Answer 2

Question 3 answer is In Attachment.

What you have to do?

Firstly Make a group of Two Same Side Number

Like.24 and 41

Subtract Smaller One From Bigger

41-24=17

And 40-25=15

Now Add the Both=17+15=32

Now Divide The Obtain sum from 2

32÷2=16

You Got Number that in Circle.

follow this and You will got 28 in Last Circle

$\boxed{\mathbf{\huge{3.(28)}}}$.

For Question 4.

Given in First Figure.

12,08=80

First Add Both Terms

12+8=20

Then Subtract

12-8=4

Now Multiply

20×4=80

You Get Main Answer as 80.

In Last Figure

Given

25,21=?

Add the terms

25+21=46

Then Subtract

25-21=4

Multiply

46×4=184

$\boxed{\mathbf{\huge{4.(184)}}}$