Question

How can we solve this equation, log (base10) x=log (base5) 2x?​

Answer 1

Step-by-step explanation:

Let y= log (base10) x=log (base5) 2x

=> 10^y= x and 5^y=2x

=> 5^y= 2 * 10^y

solving 1/2= 2^y

=> y = -1

so, x= 1/10