Physics, asked by Pritigiri8333, 4 months ago

How can we use the thre equations of motion?

Answers

Answered by harshpatna1
0

Explanation:

How can I know when I should use the 3 equations of motion in problems?

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15 Questions and Answers

Patrick Hochstenbach, Master Theoretical Physics, Radboud University, the Netherlands

Updated 6 years ago · Author has 2.7K answers and 2.5M answer views

How can I know when I should use the 3 equations of motion in problems?

Originally Answered: How can I know that when I should use the 3 equations of motion in problems?

The three equations of motions are:

1) v = v0 + aΔt

2) x = x0 + v0Δt + ½aΔt^2

3) v^2 = v0^2 + 2a(x − x0)

These are the equations you learn in the physics class at school to calculate the velocity or end position of an object given an acceleration and a time or a distance.

Let me tell you a little secret: there are no 3 equations of motion. The three things you see above follow directly from the definition of a constant acceleration in one direction. But you need a bit of calculus to see that. The 3 above are an easy way to calculate things without needing calculus.

To know which one you need requires a close examination of your physics problem. E.g.

Equation 1) you use when the physics teacher asks you to calculate a speed, given some actions during a period of time.

Equation 2) you use when the physics teacher asks you to calculate a position, given some actions during a period of time.

Equation 3) you use when the physics teachers asks you to calculate a speed, given some actions over some distance.

Lets try this out!

Equation 1: gives you a speed as answer and it needs a time as input.

What is the speed of Jan when she travels at 10 m/s without accelerating for 10 seconds?

Answer:

v0 = 10 m/s ; a = 0 m/s^2 (she isn't accelerating) ; Δt = 10 s

So, v = 10 + 0 * 10 = 10 m/s

What is the speed of Jan when she travels at 10/ms and decelerates at 10 m/s^2 for 2 seconds?

Answer:

v0 = 10 m/s ; a = -10 m/s^2 ; Δt = 2 s

So, v = 10 + -10 * 2 = - 10 m/s (she travels in the opposite direction)

Equation 2: gives you a position as answer and needs a time as input.

Jan travels at 10 m/s without acceleration where is she 10 seconds later?

Answer:

x0 = A (some point in space) ; v0 = 10 m/s ; a = 0 ; Δt = 10 s

So, x = A + 10 * 10 + ½ * 0 * 2^ 2 = A + 100 meter.

I don't know where A is but Jan is 100 meters further on her route.

Jan travels at 10 m/s , decelerates at 10 m/s^s for 2 seconds, where is she now?

Answer:

x0 = A (some point in space) ; v0 = 10 m/s ; a = -10 m/s^2 ; Δt = 2 s

So, x = A + 10 * 2 + ½ * - 10 * 2 ^ 2 = A + 20 - 20 = A

I don't know where A is but that is where Jan is now.

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