How can you combine three resistances, each of 4 Ω such that the total resistance of the circuit is 6 Ω?
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Explanation:
To get an equivalent resistance of 6 ohms, we have to use both parallel and series connection in the circuit. First, the two resistors are connected in parallel to obtain a combined resistance of 2 ohms and then the combined resistance in connected in series with the third resistor to give a total resistance of 6 ohms.That is, for the two resistors in parallel the resistance is given as
4/1 + 4/1
=
1/0.5
=2ohms andthis is added with the resistance of the third resistor in series as 2+4=6 ohms.
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