how can you connect three resistance each of 2 ohm to get maximum
resistance from a supply of 12 volt. also find the net current
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Answer:
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Explanation:
ANSWER
(a) Req =
3×2
-----
3+2
=
5
6
=1.2Ω
(b) V=IR⇒I=
R
V
⇒I=
1.2
12
=10A
(c) 3(10−i)=2i (∵ Potential drop in parallel combination are same)
⇒30−3i=2i⇒30=5i⇒i=6A
Current in 2Ω resistor is =i=6A
Current in 3Ω resistor is =10−i=4A
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