Question

How can you convert ?
i) CH3CH2CH2OH —
> CH3CH2CHO​

Answer 1

Answer:

Oxidation of $CH_{3}CH_{2}CH_{2}OH$ in the presence of $Na_{2}Cr_{2}O_{7}$ and $H_{2}SO_{4}$ to form  $CH_{3}CH_{2}CHO$ and water.

Explanation:

Propanol treated with an oxidizing agent gives propanal and water.

We can use sodium dichromate as oxidizing agent.

$CH_{3}CH_{2}CH_{2}OH$ $+[O]$  ------->$CH_{3}CH_{2}CHO + H_{2}O$

Here propanol oxidized by sodium dichromate and acidified in dilute sulfuric acid to form propanal.