Question

How can you drop two eggs the fewest amount of times, without them breaking?
No spam or I will Report to mods.
​

Answer 1

Explanation:

$\huge\underline\mathfrak\color{red} Answer$

You are given two eggs, and access to a 100-storey building. Both eggs are identical. The aim is to find out the highest floor from which an egg will not break when dropped out of a window from that floor. If an egg is dropped and does not break, it is undamaged and can be dropped again. However, once an egg is broken, that’s it for that egg.

If an egg breaks when dropped from floor n, then it would also have broken from any floor above that. If an egg survives a fall, then it will survive any fall shorter than that.

The question is: What strategy should you adopt to minimize the number egg drops it takes to find the solution?. (And what is the worst case for the number of drops it will take?)

There are no tricks, gotchas or other devious ruses. Don’t rat-hole with issues related to terminal velocity, potential energy or wind resistance. This is a math puzzle plain and simple.

hope it helps you;!

Answer 2

Answer:

Drop the egg from half way up the building. This divides the search space in half. If it breaks, start on the bottom floor and work your way up. If it doesn't, start on the next floor up and continue up