how can you find critical angle of water explain your steps carefully
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as refractive index of water is 1.33 or 4/3
we have a formula for critical angle
sinc=(1/n)
sinc =3/4
sinc = 0.75
c= sin^-1 (0.75)
c = 68° (approximately)
we have a formula for critical angle
sinc=(1/n)
sinc =3/4
sinc = 0.75
c= sin^-1 (0.75)
c = 68° (approximately)
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