how can you find the acceleration and velocity of an object moving on an inclined plane
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Answered by
1
by resolving the velocity into vsinβ and vcosβ and using f= ma
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4
Hey dear,
◆ Answer-
a = gsinθ
v = √(2sgsinθ)
◆ Explanation-
For object of mass m moving on inclined plane at angle θ, rolling force is given by-
F = mgsinθ
Acceleration is calculated by-
a = F/m = gsinθ
Final velocity is calculated by-
v^2 = u^2 + 2as
v^2 = 2sgsinθ
v = √(2sgsinθ)
Therefore,
a = gsinθ
v = √(2sgsinθ)
Hope it helps...
◆ Answer-
a = gsinθ
v = √(2sgsinθ)
◆ Explanation-
For object of mass m moving on inclined plane at angle θ, rolling force is given by-
F = mgsinθ
Acceleration is calculated by-
a = F/m = gsinθ
Final velocity is calculated by-
v^2 = u^2 + 2as
v^2 = 2sgsinθ
v = √(2sgsinθ)
Therefore,
a = gsinθ
v = √(2sgsinθ)
Hope it helps...
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