how can you find the value of tan 90 geometrically
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Let angle C be ∅
and assume that
∅ tends to at angle B that is 90°
If ∅ tends to 90° then base will reduce and become zero .
and hypotenuse will coincide with perpendicular.
( neglecting the length )
B ( base ) = 0
H ( hypotenuse ) = P ( perpendicular )
and ,
tan ∅ = P / B
tan 90 = P / 0 = N.D ( not defined )
by the same we can find all 90° value like sin , cos etc.
and assume that
∅ tends to at angle B that is 90°
If ∅ tends to 90° then base will reduce and become zero .
and hypotenuse will coincide with perpendicular.
( neglecting the length )
B ( base ) = 0
H ( hypotenuse ) = P ( perpendicular )
and ,
tan ∅ = P / B
tan 90 = P / 0 = N.D ( not defined )
by the same we can find all 90° value like sin , cos etc.
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