Question

How can you prepare 1 litre 1 N HCL solution ?​

Answer 1

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• How can we prepare 1 L , 1 N HCl solution ?

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We need to prepare I N ( read as 1 Normal ) , 1 L HCl solution . We know that Normality is defined as ,

$\sf\dashrightarrow \pink{Normality ( N ) =\dfrac{ Gram \ Equivalent \ Weight_{(solute)} }{Volume_{(Solution)}}}$

• The volume of Solution is in litres .

And where Gram Equivalent of solute is ,

$\sf\dashrightarrow Gram \ Equivalent =\dfrac{ Given\ wt.}{Equivalent\ weight}$

Therefore, the formula becomes ,

$\sf\dashrightarrow Normality ( N ) =\dfrac{ \dfrac{ Given\ wt.}{Equivalent\ weight} }{Volume}$

Now HCl , has one replaceable H+ ion , therefore the n factor is 1 . Henceforth the Equivalent weight will be ( 35.5 + 1 )/1 = 36.5 .

$\sf\dashrightarrow 1\ N = \dfrac{ \dfrac{W}{36.5}}{1L } \\\\\\\sf\dashrightarrow\boxed{\sf \red{ W = 36.5 \ g}}$

Hence we need to add 36.5 g/L of HCl to Solution to prepare 1N solution.