How can you use a point on the graph of f –1(x) = 9x to determine a point on the graph of f(x) = log9x?
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Given: f^-1 (x) = 9x, f(x) = log9x
To find: use a point f^-1(x) = 9x to determine a point f(x) = log9x
Solution:
- As we have given the inverse function, so very first we should understand that graph of the given function and graph of that inverse function are mirror image of each other, which means they are mirror image with respect to the line x=y.
- To get the function from its inverse we can swap the coordinates of inverse function to get the original function as inverse is the mirror image of the original function.
- For example, all the logarithmic functions pass through the point (1,0) and all exponential functions pass through the point (0,1).
Answer:
By swapping the x and y coordinates, we can use point f^-1(x) = 9x to determine point of f(x) = log9x.
Answered by
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Answer: switch the x- and y-coordinates
Step-by-step explanation:
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