How could the function y=3t2+4 be plotted on a Cartesian graph to produce a straight line? What would be the numerical values of the slope and intercept of the line?
Answers
Answer:
Let x = t^2 and use equal increments of t^2 along the x axis, when plotting y vs x.
For t = 0, x = 0.
For t = 1, x = 1.
For t = 1.414, x = 2
For t = 1.732, x = 3 .
For t= 2, x = 4, etc.
The slope of the line you get will be 3.
Explanation:
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Answer:
The values of the slope and intercept of the line will be 3 and 4 respectively.
Explanation:
It is given that, y= 3t² + 4
According to the general equation of slope and intercept is= y= mx+ b
Where, m = slope and b = intercept of the line.
The slope and the intercept of the given equation is needed to be found.
Let, x²= P
so, the given equation ca be written as y= 3P + 4.
The given equation is compared to the general equation.
Now comparing the equations, m= 3 and b= 4.
Now, for the graph-
y= 3P + 4
On P = 0, y= 4
and on y= 0, P= -4/3
So, values of the slope and intercept of the line will be 3 and 4 respectively.
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