Physics, asked by DungeonMaster84, 4 months ago

How could the function y=3t2+4 be plotted on a Cartesian graph to produce a straight line? What would be the numerical values of the slope and intercept of the line?

Answers

Answered by chhavitomar76
4

Answer:

Let x = t^2 and use equal increments of t^2 along the x axis, when plotting y vs x.

For t = 0, x = 0.

For t = 1, x = 1.

For t = 1.414, x = 2

For t = 1.732, x = 3 .

For t= 2, x = 4, etc.

The slope of the line you get will be 3.

Explanation:

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Answered by Iammanjula
0

Answer:

The values of the slope and intercept of the line will be 3 and 4 respectively.

Explanation:

It is given that, y= 3t² + 4

According to the general equation of slope and intercept is= y= mx+ b

Where, m = slope and b = intercept of the line.

The slope and the intercept of the given equation is needed to be found.

Let, x²= P

so, the given equation ca be written as y= 3P + 4.

The given equation is compared to the general equation.

Now comparing the equations, m= 3 and b= 4.

Now, for the graph-

y= 3P + 4

On P = 0, y= 4

and on y= 0, P= -4/3

So, values of the slope and intercept of the line will be 3 and 4 respectively.

To learn more, please visit:

https://brainly.in/question/18532888

https://brainly.com/question/10606041

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