Math, asked by Khayez9590, 1 year ago

how cylindrical coordinate system are mutually perpendicular?

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Answered by calidris
0

The cylindrical coordinate system is obtained as

 x=r\cos \phi , y=r\sin \phi , z=Z

The ranges of  \hat{r}, \hat{\phi }, \hat{z} as

 0\leq r\leq \infty  \\0\leq \phi \leq 2\pi  \\ -\infty <z\leq \infty

The Cartesian unit vector as of cylindrical coordinate system as

 \hat{r}=\cos \phi  \hat{x}+\sin {\phi }\hat{y}

 \hat{r}=-\sin \phi  \hat{x}+\cos {\phi }\hat{y}

 \hat{Z}=\hat{z}

To verify that this unit vectors are mutually perpendicular.

 \hat{r}\cdot \hat{\phi }=0\\\hat{\phi}\cdot \hat{z }=0\\\hat{r}\cdot \hat{z }=0

Thus the cylindrical coordinate system are mutually perpendicular.

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