How did it become from
l2+ 2lm + m2–4lm
to l2–2lm + m2
?
Attachments:
Answers
Answered by
0
Answer:
l²+2lm+m²-4lm
l²+m²+2lm-4lm
l²+m²-4lm ( same quantity get cancel out and sign is of the greater one )
Answered by
0
Answer:
=l
2
+2.l.m+m
2
−4lm
=l
2
+2lm+m
2
−4lm
\begin{gathered} = {l}^{2} - 2lm + {m}^{2} \\ \\ = {(l - m)}^{2} \\ \\ = (l - m)(l - m)\end{gathered}
=l
2
−2lm+m
2
=(l−m)
2
=(l−m)(l−m)
Similar questions