Question

How did we get x=-3 root2 /2 or x=root2/4 plz explain me

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Answer 1

That is called as rationalization.

(1) 

$\sqrt{2} x + 3 = 0  [tex] \sqrt{2} x = -3$

$x = \frac{-3}{ \sqrt{2} }$

$x = - \frac{3}{ \sqrt{2} } * \frac{ \sqrt{2} }{\sqrt{2}}$

$x = - \frac{3 \sqrt{2} }{ \sqrt{2} * \sqrt{2} }$

$x = - \frac{ 3\sqrt{2} }{2}$




(2) 

$2 \sqrt{2}x - 1 = 0$

$2 \sqrt{2} x = 1$

$x = \frac{1}{2 \sqrt{2} }$

$x = \frac{1}{2 \sqrt{2} } * \frac{2 \sqrt{2} }{2 \sqrt{2} }$

$x = \frac{2 \sqrt{2} }{2 * 4}$

$x = \frac{2 \sqrt{2} }{8}$

$x = \frac{ \sqrt{2} }{4}$




Hope this helps!