Question

How do i calculate the number of moles present in 9g of ethane?

Answer 1

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Answer 2

Answer:

one gram of ethane contains 1/30 mole of ethane, similarly by multiplying 1/30 with 9, we will find the number of mole of ethane contained by 9 grams of ethane. So, 9 gram of ethane equals to 9(1/30)=3/10=0.3 moles of ethane.

Explanation:

What is the number of moles present in 9g of ethane?

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Atomic mass of C- atom = 12

Atomic mass of H- atom = 1

1 mole Ethane C2H6 consists of 2 C-atoms (12 g each) and 6 H-atoms (1 g each).

So, M. Wt. of Ethane =M= 24+6 = 30

So n=m/M

where n is no. of moles, m is the mass of substance, M is the molar mass

m = 9g M = 30

n = 9/30 = 0.3 moles.

Ethane is an alkane with a molecular formula of C2H6, by summing up the respective atomic masses of it's constituent atoms we can find out the molecular weight which equals to (12x2+1x6)=30.

Now, one mole of ethane weighs 30 grams,

So, one gram of ethane contains 1/30 mole of ethane, similarly by multiplying 1/30 with 9, we will find the number of mole of ethane contained by 9 grams of ethane.

So, 9 gram of ethane equals to 9(1/30)=3/10=0.3 moles of ethane.

The answer is 0.3 moles of ethane

Mass of the Ethane = 9 g.

Chemical Formula of the Ethane = C₂H₆

∴ Molar mass of the ethane = 12 × 2 + 1 × 6

 = 24 + 6

 = 30

∵ No. of moles = Mass/Molar mass

∴ No. of moles of the Ethane = 9/30

   = 3/10

   = 0.3 moles.

Hence, the number of the moles in 9 g of the Ethane is 0.3 moles.