How do I calculate the widest gap a motor cycle rider can cross at a velocity of 100 km/h having the angle of incline on either side be 45 degrees?
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Answer:
Explanation:
Horizontal distance covered between the, time taken while it leaves the ground at the start of the gap at angle of 45° ,& then touces the ground at the end of the gap to be found out.
0=( 100* 5/18)(sine45°) - gt
t= 100*5/18✓2g . ( Time to go up& lose vertical part of the velup)
Total time in the air= 2 t= 100*5*✓2/18 g=
= 50✓2/18 sec
Horizontal gap it can cross is
(100*5/18/✓2)*50*✓2/18
= 100*5*50/18*18
=2500/18*18
= 77.16m
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