How do I do this? (Check the picture).
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then PQ=3cm
by Pythagoras theorem
in circle
CO is radius.=5cm
CQ is mid point of CD =4cm
then PQ=3cm
by Pythagoras theorem
in circle
CO is radius.=5cm
CQ is mid point of CD =4cm
then PQ=3cm
PrachiMaheshwari:
see Q is the midpoint of CD... so the length of CQ / DQ = 4 cm.....draw a segment from O to D point.... that's radius....& it's length is 5 cm .... so accommodating to Pythagoras theorem....the length of OQ = 3 cm..
& PO is radius having length 5cm .... so PO - OQ =
PO - OQ = PQ. .....…thus 5-3 =2cm
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see the point Q is the midpoint of CD....
therefore QC=QD=4cm
draw a radius joing point D ,i.e., OD
OD= 5cm
according to Pythagoras theorem
the length of OQ= 3cm
then 5 - 3= 2cm
mark brainliest if you like it
therefore QC=QD=4cm
draw a radius joing point D ,i.e., OD
OD= 5cm
according to Pythagoras theorem
the length of OQ= 3cm
then 5 - 3= 2cm
mark brainliest if you like it
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