How do I evaluate ∫π0sin(x)dx?
Answers
Answered by
0
Answer:
2
Explanation:
Given:
∫
π
0
sin
(
x
)
d
x
.
=
[
−
cos
(
x
)
]
π
0
=
−
cos
(
π
)
−
(
−
cos
(
0
)
)
=
−
cos
(
π
)
+
cos
(
0
)
=
−
(
−
1
)
+
1
=
1
+
1
=
2
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