Question

How do i evaluate integration of (5+3x-6x^2-7x^4-8x^6) / x^6 dx?

Answer 1

Answer:

-1/x^5 -3/4x⁴+2/x³+7/x-8x + C

Step-by-step explanation:

I=(5+3x-6x²-7x⁴-8x^6)/x^6 dx

I=(5/x^6+3x/x^6 -6x²/x^6 -7x⁴/x^6 -8x^6/x^6)dx

I=5x^-6+3x^-5 -6x^-4 -7x^-2-8)dx

:- use the formula x^n = {x^(n+1)}/(n+1)

I=-5×1/5x^5 -3/4x^4 +2/x³+7/x-8x +c

-1/x^5 -3/4x⁴ +2/x³+7/x -8x +C