Question

how do i expand (5y-1) (y+2)​

Answer 1

$(5y - 1)(y + 2) \\ 5y(y + 2) - 1(y + 2) \\ {5y}^{2} + 10y - y - 2 \\ {5y}^{2} + 9y - 2 \\ {5y}^{2} + (10 - 1)y - 2 \\ {5y}^{2} + 10y - y - 2 \\ 5y(y + 2) - 1(y + 2) \\ (5y - 1)(y + 2) = 0 \\ y = \frac{1}{5} \\ y = - 2$

Answer 2

(5y−1)(y+2)

5y(y+2)−1(y+2)

5y

2

+10y−y−2

5y

2

+9y−2

5y

2

+(10−1)y−2

5y

2

+10y−y−2

5y(y+2)−1(y+2)

(5y−1)(y+2)=0

y=

5

1

y=−2