Question

How do I factor 8x3−1 completely?

Answer 1

Solution:

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We know the algebraic identity:

a³-b³ = (a-b)(a²+ab+b²)

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Here,

8x³ - 1

= (2x)³ - 1³

= (2x-1)[(2x)²+(2x)*1+1²]

= (2x-1)(4x²+2x+1)

Therefore,

8x³ - 1 = (2x-1)(4x²+2x+1)

•••

Answer 2

Hey!

Refer the below attachment !

Thanks!