Math, asked by exampleexample, 9 months ago

How do I find (1901+1902+...+1993)-(101-102+...+193)?

Answers

Answered by Anonymous
1

Hey Buddy

Here's The Answer

-------------------------------------

Now , we can break

1901 = 1800 + 101

and further

( 1901 + 1902 + ...+ 1993 ) - ( 101 + 102 +...+ 193 )

Now breaking

( 1800 + 101 + 1800 + 102 +...+ 1800 + 193 ) - ( 101 + 102 +...+ 193 )

( 1800 × 93 ) + (101 + 102+...+193 ) - ( 101 + 102 +...+ 193 )

Now final expression

1800 × 93

167400

Note :- These are tricky questions, don't get panic after seeing such questions, just observe the pattern. Good Luck

HOPE HELPED

:)

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