Question

how do i find area of a triangle?

Answer 1

$Area\ of\ triangle = \frac{1}{2} bh\\\\area \ of \ triangle = \sqrt{s(s-a)(s-b)(s-c)} \\\\\\\\Area\ of\ triangle = \frac{1}{2} bh \\\\here \ , b = base , \ h = perpendicular \ height\\\\\\area \ of \ triangle = \sqrt{s(s-a)(s-b)(s-c)} \\\\here \ , s = semi-perimeter , \ a,b,c => three\ sides \ of \ the \ triangle\\\\hope \ it \ helps \ !!$