Question

How do i find the tangent of angle b?
it’s a right triangle. side ab is 12, bc is 7, and ac is square root of 95

Answer 1

Step-by-step explanation:

AC^2 + BC^2 = (√95)^2 + 7^2 = 95+49=144=12^2 = AB^2

So ABC IS a right triangle right angled at C

so tanB = opposite/ adjacent

= AC/BC

tanB = √95/7

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