Question

how do i solve 2sinx-1=cscx in degrees
0°≤ x < 360°

Answer 1

Step-by-step explanation:

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Answer 2

Answer:

x = 330˚, 210˚, 90˚

Rewrite in terms of sine.

Step-by-step explanation:

2sinx−1=1sinxsinx(2sinx−1)=

12sin2x−sinx−1=02sinx−2sinx+sinx−1 =

02sinx(sinx−1)+1(sinx−1)

=0(2sinx+1)(sinx-1)=0

sinx=−12 or sinx=1

When

sinx=−12

we will be in the 3rd and 4th quadrants. Therefore,

x=180˚+30˚=210˚

and x=360˚−30˚=330°

When sinx=1, x will equal 90˚.

Hopefully this helps!