Math, asked by onlyave30, 10 days ago

how do i solve 2sinx-1=cscx in degrees

Answers

Answered by sribhanu316
0

Answer:

2 \sin(x)  - 1 =  \csc(x)

2 \sin(x)  =  \frac{1}{ \csc(x) }   + 1

2 \sin(x)  =  \sin(x)  + 1

2 \sin(x)  -  \sin(x)  = 1

 \sin(x)  = 1

Similar questions