How do I solve 3x^2-4x=6x-3
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your answer is 3 or 1/3 ...
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varun2003k:
thanks
Answered by
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hey mate!!
by factorisation method
3x^2-4x-6x+3=0
3x^2-10x+3=0
3x^2-9x-x+3=0
3x(x-3)-1(x-3)=0
(3x-1)(3x-3)=0
3x-1=0. and 3x-3=0
X=1/3. or X=3/3=1
I hope it helped
by factorisation method
3x^2-4x-6x+3=0
3x^2-10x+3=0
3x^2-9x-x+3=0
3x(x-3)-1(x-3)=0
(3x-1)(3x-3)=0
3x-1=0. and 3x-3=0
X=1/3. or X=3/3=1
I hope it helped
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