Question

how do I solve Qs.30 ???
(20 points in offer and first one to answer is marked at brainliest.)

Answer 1

it is easy 

just take triangle ABP and CBQ 

given that --  AB = BC 
                     ∠ABP = ∠CBQ
                     ∠PBD = ∠QBD

so it Δ  ABP congruent to Δ  CBQ { by ASA congruence rule }

∴ PB = PQ { by CPCT = Congruent part of congruent triangle }