How do I solve quadratic equation for x--> x²+(x²/(x+1)²) =3?
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Answered by
5
HEY MATE HERE IS YOUR ANSWER
x2+x2(x+1)2=3x2+x2(x+1)2=3
x2+(xx+1)2=3x2+(xx+1)2=3
x2+(1−1x+1)2=3x2+(1−1x+1)2=3
x2+1−2x+1+(1x+1)2=3x2+1−2x+1+(1x+1)2=3
x2+2−2x+1+(1x+1)2=4x2+2−2x+1+(1x+1)2=4
x2+2x+2−2x+1+(1x+1)2=4x2+2x+2−2x+1+(1x+1)2=4
x2+2xx+1+(1x+1)2=4x2+2xx+1+(1x+1)2=4
(x+1x+1)2=4(x+1x+1)2=4
x+1x+1=±2x+1x+1=±2
x=1±5√2x=1±52, −3±i3√2−3±i32
x2+x2(x+1)2=3x2+x2(x+1)2=3
x2+(xx+1)2=3x2+(xx+1)2=3
x2+(1−1x+1)2=3x2+(1−1x+1)2=3
x2+1−2x+1+(1x+1)2=3x2+1−2x+1+(1x+1)2=3
x2+2−2x+1+(1x+1)2=4x2+2−2x+1+(1x+1)2=4
x2+2x+2−2x+1+(1x+1)2=4x2+2x+2−2x+1+(1x+1)2=4
x2+2xx+1+(1x+1)2=4x2+2xx+1+(1x+1)2=4
(x+1x+1)2=4(x+1x+1)2=4
x+1x+1=±2x+1x+1=±2
x=1±5√2x=1±52, −3±i3√2−3±i32
Parasar1980:
Hey thanks!
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now please mark brainliest ans81
Answered by
0
HEY MATE HERE IS YOUR ANSWER
x2+x2(x+1)2=3x2+x2(x+1)2=3
x2+(xx+1)2=3x2+(xx+1)2=3
x2+(1−1x+1)2=3x2+(1−1x+1)2=3
x2+1−2x+1+(1x+1)2=3x2+1−2x+1+(1x+1)2=3
x2+2−2x+1+(1x+1)2=4x2+2−2x+1+(1x+1)2=4
x2+2x+2−2x+1+(1x+1)2=4x2+2x+2−2x+1+(1x+1)2=4
x2+2xx+1+(1x+1)2=4x2+2xx+1+(1x+1)2=4
(x+1x+1)2=4(x+1x+1)2=4
x+1x+1=±2x+1x+1=±2
x=1±5√2x=1±52, −3±i3√2−3±i32
x2+x2(x+1)2=3x2+x2(x+1)2=3
x2+(xx+1)2=3x2+(xx+1)2=3
x2+(1−1x+1)2=3x2+(1−1x+1)2=3
x2+1−2x+1+(1x+1)2=3x2+1−2x+1+(1x+1)2=3
x2+2−2x+1+(1x+1)2=4x2+2−2x+1+(1x+1)2=4
x2+2x+2−2x+1+(1x+1)2=4x2+2x+2−2x+1+(1x+1)2=4
x2+2xx+1+(1x+1)2=4x2+2xx+1+(1x+1)2=4
(x+1x+1)2=4(x+1x+1)2=4
x+1x+1=±2x+1x+1=±2
x=1±5√2x=1±52, −3±i3√2−3±i32
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