how do I solve this
(1/2)^3=8^x-2
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Heya ✋
Let see your answer !!!
(1/2)^3 = 8^x-2
=> 2^-3 = 2^3(x - 2)
=> 2^-3 = 2^3x-6
=> Since bases are same
=> -3 = 3x - 6
=> - 3x = - 6 + 3
=> -3x = -3
=> x = -3/-3
=> x = 1
Thanks :)))))
Let see your answer !!!
(1/2)^3 = 8^x-2
=> 2^-3 = 2^3(x - 2)
=> 2^-3 = 2^3x-6
=> Since bases are same
=> -3 = 3x - 6
=> - 3x = - 6 + 3
=> -3x = -3
=> x = -3/-3
=> x = 1
Thanks :)))))
DizasterMaster:
thanks.....that was very nice of you!
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