Question

how do i solve this???​

Answer 1

Answer:

Ans) 1

Refer to the attachement for the solution.

Step by step explanation :-

As we know about complementary angles in trigonometry,

So, the formula used here are :

Sin (90-a)=cos a

Cos(90-a)=sin a

$= > \frac{ { \sin(15) }^{2} + { \sin(75) }^{2} }{ { \cos(36) }^{2} + { \cos(52) }^{2} }$

$= > \frac{ { \sin(90 - 75) }^{2} + { \sin(75) }^{2} }{ { \cos(90 - 52) }^{2} + { \cos(52) }^{2} }$

$as \: {sin}^{2} a + {cos}^{2} a \: = 1$

Therefore,

$= > \frac{ { \cos(75) }^{2} + { \sin(75) }^{2} }{ { \sin(52) }^{2} + { \cos(52) }^{2} }$

$= > \: \: \: \: 1$