Chemistry, asked by Hunter21, 1 year ago

How do I solve this question :- A solution of HCl has pH=5 if 1 ml of it is diluted to 2 litre, calculate the pH of resulting solution? Include the calculation also? With explanations

Answers

Answered by shivam8899
30
as we know
 if pH = 5 then concentration
pH = - log(H+)
then 
5 = - log(H+)
then concentration = 10^-5 M
 and 

Molarity of the diluted solution is given as:

V1 = 1 ml and V2 = 2000 ml 

M1 V1 = M2 V2

10^-5 x 1 = M2 x 2000 

M2 = 5 x 10^-9 M

and now pH = - log (5 x 10^-9)

pH = 9 - log5

pH = 9 - 0.7 = 8.3 M



i hope it will help you 
regard

Answered by omkardumbhare
18

pay attention to these type of questions looks easy but are twisted somewhat ...

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