How do I solve this question :- A solution of HCl has pH=5 if 1 ml of it is diluted to 2 litre, calculate the pH of resulting solution? Include the calculation also? With explanations
Answers
Answered by
30
as we know
if pH = 5 then concentration
pH = - log(H+)
then
5 = - log(H+)
then concentration = 10^-5 M
and
regard
if pH = 5 then concentration
pH = - log(H+)
then
5 = - log(H+)
then concentration = 10^-5 M
and
Molarity of the diluted solution is given as:
V1 = 1 ml and V2 = 2000 ml
M1 V1 = M2 V2
10^-5 x 1 = M2 x 2000
M2 = 5 x 10^-9 M
and now pH = - log (5 x 10^-9)
pH = 9 - log5
pH = 9 - 0.7 = 8.3 M
regard
Answered by
18
pay attention to these type of questions looks easy but are twisted somewhat ...
Attachments:
Similar questions