How do I work this using the substitution method?
x-y=3
x+2y=-3
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Answer :
Given two equations are -
x-y=3 (a)
x+2y=-3 (b)
To find ,
values of x and y
Main solution :
In the first equation x - y = 3
From this ,
x = y + 3 ( i )
We know the other linear equation in x and y is
x + 2y = - 3
Now , substituting the value of x from (i) in this equation , we get :
y + 3 + 2y = -3
Now solving for y using transposition :
3y + 3 = -3
3y = -6
y = -2
Now putting the value of y in equation (a) to find the value of x
x - ( - 2 ) = 3
x + 2 = 3
x = 1
Therefore ,
Value of x = 1 and Value of y = -2
Given two equations are -
x-y=3 (a)
x+2y=-3 (b)
To find ,
values of x and y
Main solution :
In the first equation x - y = 3
From this ,
x = y + 3 ( i )
We know the other linear equation in x and y is
x + 2y = - 3
Now , substituting the value of x from (i) in this equation , we get :
y + 3 + 2y = -3
Now solving for y using transposition :
3y + 3 = -3
3y = -6
y = -2
Now putting the value of y in equation (a) to find the value of x
x - ( - 2 ) = 3
x + 2 = 3
x = 1
Therefore ,
Value of x = 1 and Value of y = -2
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