How do solve the following linear system?: 4x+3y=1,2x+5y−21=0?
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4x+3y=1...(1)
-2(2x+5y=21)...(2)
-7y=-41
y=41/7
on putting the value of y in equ..(1)
we get,
=4x+3×41/7=1
=4x=1-123/7
=4x=-116/7
x=-116/7×4
x=-58/21
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