How do the coefficient of x³in 4x³-3x+9 is solved
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in general, if we have polynomial like
then,
coefficient of x^3=a
coefficient of x^2=b
coefficient of x =c
so here coefficient of x^3=4......answer
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then,
coefficient of x^3=a
coefficient of x^2=b
coefficient of x =c
so here coefficient of x^3=4......answer
mark as brainliest if helped
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