Question

How do u do this???
Is it important for exams..?

Answer 1

squaring both sides we get
x^2=2+
$\sqrt{2 + \sqrt{2} }$
....
${x}^{2} = 2 + x$
${x}^{2} - x - 2 = 0$
${x}^{2} - 2x - + x - 2 = 0$
$x(x - 2) + 1(x - 2)$
x+1=0 or x-2=0
x=-1 or x=2