How do we factorise 162-8r^2
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162-8r²
by taking 2 common from both the terms , we have ,
=> 2 (81-4r²)
=> 2 [(9)² - (2r)²]
using a²-b² = (a+b)(a-b)
=> 2 [9-2r][9+2r]
=> 2 (9-2r)(9+2r)
hope this helps
by taking 2 common from both the terms , we have ,
=> 2 (81-4r²)
=> 2 [(9)² - (2r)²]
using a²-b² = (a+b)(a-b)
=> 2 [9-2r][9+2r]
=> 2 (9-2r)(9+2r)
hope this helps
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