How do we find force to derive $pV=Nmv^2$?
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Since momentum is not changing in time t , but instantaneously in very small time at wall B.
Why do we write F=2mvtF=2mvt? Where tt is (twice the distance AB)/ velocity.
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Since momentum is not changing in time t , but instantaneously in very small time at wall B.
Why do we write F=2mvtF=2mvt? Where tt is (twice the distance AB)/ velocity.
I hope its help you plzz mark me brainliest ans and follow me
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Therefore the force exerted by this single wall collision is simply d( dt mv) F = ma = (5.1) or ∆ F ... Rearranging this, for an ideal gas PV Nmv nRT L X m VX = 2 x = = N N A RT = NkT ...
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