Question

How do we get the displacement of a particle in a time interval t1 to t2 from its velocity -time graph?

Answer 1

Answer:

Explanation:

speed of light in free space,

c = 3.00  108

m s

-1

permeability of free space,

o = 4  10-7

H m

-1

permittivity of free space,

o = 8.85  10-12

F m

-1

 (1/(36))  10-9

F m

-1

elementary charge,

e = 1.60  10

-19 C

the Planck constant,

h = 6.63  10- 34

J s

unified atomic mass constant,

u = 1.66  10-27

kg

rest mass of electron,

me = 9.11  10-31

kg

rest mass of proton,

mp = 1.67  10-27

kg

molar gas constant,

R = 8.31 J K-1

mol

-1

the Avogadro constant,

NA = 6.02  1023

mol

-1

the Boltzmann constant,

k = 1.38  10-23

J K

-1

gravitational constant,

G = 6.67  10-11

N m

2

kg

-2

acceleration of free fall,

g = 9.81 m s