How do we get the formula
Displacement =ut+1/2at^2
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acceleration = change in velocity per unit time
= (v-u)/t where v-final velocity and u-initial velocity
v-u=at
v=u+at
we know that displacement per unit time is velocity
v= ds/dt
ds/dt = u + at
integrating on both sides then
since integral of x^n = (x^n+1)/n+1
s= ut + 1/2 at^2 + c
when time is 0 then the body's displacement is also zero
so t=0 , s=0 then c=0
therefore s= ut+1/2 at^2
= (v-u)/t where v-final velocity and u-initial velocity
v-u=at
v=u+at
we know that displacement per unit time is velocity
v= ds/dt
ds/dt = u + at
integrating on both sides then
since integral of x^n = (x^n+1)/n+1
s= ut + 1/2 at^2 + c
when time is 0 then the body's displacement is also zero
so t=0 , s=0 then c=0
therefore s= ut+1/2 at^2
Siddharth4444:
it's a bit complex I guess...
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