Question

How do we know that numbers a,b and c are in the form of equation (a+b)² or
(a-b)² ?
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Answer 1

Answer:

If the equation includes the the given variables as the formulas of the expansion , we can identify the form of formula .

For example , if the equation is :

(*please note a and b are variables which may have a number in its place .)

a^2 +b^2 + 2ab

then it is the form (a+b)^2

and if it is like ,

a^2 + b^2 - 2ab , then it is the expanded form of (a-b)^2.

Hope this helps.

Have a nice day !

Answer 2

Answer:

a) V₀ = 13.5m/s

a) V₀ = 13.5m/sb) a = 2.1 m/s²

Explanation:-

1) Convert velocities to m/s

i) 20 km/h × 1000m/kg × 1h/3600s = 5.556m/s

ii) 40km/h = 11.111m/s

2) Red car, time elapsed to reach position x = 44.5m

Constant velocity ⇒ x = V×t ⇒ t = x / V

⇒ t₁ = 44.5m / 5.556m/s = 8s

3) Red car, time elapsed to reach position x = 77.6m

t₂ = 76.6m / 11.111/s = 6.9s

4) Green car, distance run at t₁ = 8s, x = 44.5m

i) uniform acceleration equation d = V₀t + at² / 2

ii) d = 220m - x = 220m - 44.5m = 175.5m = V₀ (8) + a (8)² /2

175.5 = 8V₀ + 32a ↔ equation (1)

5) Green car, distance run at t₂ = 6.9s, x = 76.6m

i) d = 220m - x = 220m - 76.6m = 143.4

ii) 143.4 = V₀t₂ + at₂² / 2

143.4 = V₀ (6.9) + a(6.9)² / 2

143.4 = 6.9V₀ + 23.8a ↔ equation (2)

6) Solve the system of equations:

175.5 = 8V₀ + 32a ↔ equation (1)

143.4 = 6.9V₀ + 23.8a ↔ equation (2)

V₀ = 13.5m/s

a = 2.1 m/s²

So the answer is (a-b)^2