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Angle TPS = 1/2( angleQ - angle R)
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Given; PS is bisector of angle QPR
PT is perpendicular to QR
To Prove; angle TPS = 1/2 (angle Q - angle R)
Solutio; We know that angle QPS = 1/2 angle P (1)
angle Q + angle QPT = 90 degree
angle QPT = 90 degree -angle Q (2)
On putting equations (1) and (2)
angle TPS = angle QPS - angle QPT
= 1/2 angle P - ( 90 - angle Q )
= 1/2 angle P - 90 + angle Q
= 1/2 angle P - 1/2 (angle Q + angle P + angle R) + angle Q
= 1/2 angle P - 1/2 angle Q - 1/2 angle P - 1/2 angle R + angle Q
= -1/2 angle Q - 1/2 angle R + angle Q (+ve and -ve 1/2 angle P got cancled )
by takig LCM in angle Q we get
-1/2 angle Q + 2/2 angle Q - 1/2 angle R
(-1/2 + 2/2) angle Q - 1/2 angle R
= 1/2 angle Q - 1/2 angle R
angle TPS = 1/2 ( angle Q -1/2 angle R ) (Hence proved)
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Given; PS is bisector of angle QPR
PT is perpendicular to QR
To Prove; angle TPS = 1/2 (angle Q - angle R)
Solutio; We know that angle QPS = 1/2 angle P (1)
angle Q + angle QPT = 90 degree
angle QPT = 90 degree -angle Q (2)
On putting equations (1) and (2)
angle TPS = angle QPS - angle QPT
= 1/2 angle P - ( 90 - angle Q )
= 1/2 angle P - 90 + angle Q
= 1/2 angle P - 1/2 (angle Q + angle P + angle R) + angle Q
= 1/2 angle P - 1/2 angle Q - 1/2 angle P - 1/2 angle R + angle Q
= -1/2 angle Q - 1/2 angle R + angle Q (+ve and -ve 1/2 angle P got cancled )
by takig LCM in angle Q we get
-1/2 angle Q + 2/2 angle Q - 1/2 angle R
(-1/2 + 2/2) angle Q - 1/2 angle R
= 1/2 angle Q - 1/2 angle R
angle TPS = 1/2 ( angle Q -1/2 angle R ) (Hence proved)
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