How do you calculate [NO−3] if 120 mL of 0.40 M KNO3 is mixed with 400 mL of 1.2 M Pb(NO3)2?
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M1V1 + M2V2 = MV
0.4x120 + 1.2x400 = M x (120+400)
M = 96/620 = w x 1000/ molecular mass + volume
weight = 96 x( 62+620)/1000 x 620
= 0.1056 g
0.4x120 + 1.2x400 = M x (120+400)
M = 96/620 = w x 1000/ molecular mass + volume
weight = 96 x( 62+620)/1000 x 620
= 0.1056 g
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