Question

How do you calculate the heat of fusion △Hf of ice?
Mass of empty cup: 4.6 g
Mass of cup + heated water: 77.6 g
Starting temperature of the water: 57.1 c
Final temperature of ice/water mixture: 0.9 c
Mass of cup + cool water: 130.6

Answer 1

Answer:

You find the mass of the heated water by substracting the mass of cup from mass of cup and heated water

Interpete the question

Energy released by heated water = Energy required to change the state of water

you then take that mass of heated water and substitute in the equation

Q=mcΔ∅

you calculate then the mass of the cool water

and substitute into

Q=mlf

equate the two equations to find for

lf which are refer to ΔHf

you take Δ∅=57.1-0.9

=56.2°C

Explanation: